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rang. kapasitor

Besarnya muatan pada kapasitor C5 adalah….

a. 36 Coulomb

b. 24 Coulomb

c. 12 Coulomb

d. 6 Coulomb

e. 4 Coulomb

Pembahasan Soal :

1/C seri1 = 1/c2+1/c3 = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 ——> C seri1= 2 F

1/C ser2 = 1/c4 + 1/c5 = 1/12 + 1/6 = 1/12 + 2/12 = 3/12——-> C seri2 = 4 F

C paralel = C seri1 + C seri 2 = 2 F + 4 F = 6 F

1/C seri 3 = 1/c1 = 1/C paralel = 1/6 + 1/6 = 2/6 ——> Cseri 3 = C total = C pengganti 5 Kapsitor = 3 F

Q Total = C total X V total = 3 x 12 = 36 Coulomb = Q 1 = Q 2,3,4,5 = 36 Coulomb

V1 = Q1/C1 = 36/6 = 6 Volt——> V2,3,4,5 = Vtotal – V1 = 12-6 = 6 Volt

V2,3,4,5 =V Paralel= V2,3= V4,5 = 6 Volt-

Q2,3= V2,3 X C2,3 = 6 X 12 = 12 Coulomb

Q4,5 = V4,5 X C4,5 = V4,6 X C seri 2 = 6 x 4 = 24 Coulomb

Q Seri = Q4,5 = Q4 = Q5 = 24 Coulomb

Jawaban yang benar (b) 24 Coulomb